14x^2+8x=6

Solution for 14x^2+8x=6 equation:

14x^2+8x=6

We move all terms to the left:

14x^2+8x-(6)=0

a = 14; b = 8; c = -6;
Δ = b2-4ac
Δ = 82-4·14·(-6)
Δ = 400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{400}=20$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-20}{2*14}=\frac{-28}{28}
=-1
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+20}{2*14}=\frac{12}{28}
=3/7
$